This was the original thread I was following
Following this recipe by @
Randy Holmes-Farley
Manganese(II) chloride tetrahydrate is 28% manganese by weight.
Here's a recipe:
Dissolve 1 gram in 100o mL (grams) fresh water. Manganese = 280 ppm.
Take 1 mL (1 g) of that mix and dissolve in 1000 mL of fresh water. Mn = 0.28 ppm (=280 ug/L).
Add 1 mL of that to 100 mL of fresh water. Mn = 2.8 ug/L
Add 13.5 mL of that to 100 gallons of tank water. Conc boost to tank = 0.1 ug/L Mn.
To me the 0.1ug/L did not look right as seawater in 0.01ppm which is 10ug/L
Please correct me if i'm wrong but this is my calculation
Dissolve 1 gram in 1000 mL (grams) fresh water. Manganese = 280 ppm = 280,000ug/L
Take 1 mL (1 g) of that mix and dissolve in 1000 mL of fresh water. Mn = 0.28 ppm (=280 ug/L).
Therefore if my tank is 350L dosing 1ml would be 0.8ug/l so to get 10ug/L (0.01ppm) would require 13ml which I would dose in 1ml increments to be safe.
Doesn't appear there is a Manganese test kit around type in Manganese and you get Magnesium.
Thanks very much for your reply